What is the foci (y+3)^2=4(x-3) ?

The foci (y+3)^2=4(x-3) is (4,-3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (y+3)^2=4(x-3)

foci

(y + 3)^{2} = 4 (x - 3)

(4, - 3)

Solution steps

Rewrite

(y + 3)^{2} = 4 (x - 3)

in the standard form:

4 \cdot 1 \cdot (x - 3) = (y - (- 3))^{2}

(h, k) = (3, - 3), p = 1

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(3, - 3)

along the x-axis

(3 + p, - 3)

= (3 + 1, - 3)

Refine

(4, - 3)

y = - 2 x^{2} + 24 x

(x - 1)^{2} = 8 (y + 3)

x^{2} = 36 y

x^{2} - 3 x + 2

y = 4 x^{2} - 8 x + 1