What is the foci y= 2/(3.3)x^2-4x+6.6 ?

The foci y= 2/(3.3)x^2-4x+6.6 is (3.3,0.4125)

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foci y= 2/(3.3)x^2-4x+6.6

foci

y = \frac{2}{3.3} x^{2} - 4 x + 6.6

(3.3, 0.4125)

Solution steps

Rewrite

y = \frac{2}{3.3} x^{2} - 4 x + 6.6

in the standard form

4 \cdot 0.4125 (y - 0) = (x - 3.3)^{2}

(h, k) = (3.3, 0), p = 0.4125

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(3.3, 0)

along the y-axis

(3.3, 0 + p)

= (3.3, 0 + 0.4125)

Refine

(3.3, 0.4125)

- 3 x^{2} + 5 x - 4

(x - 5)^{2} - 4

(- 20 x + 13)^{2}

2 x^{2} + 4 x - 16

- x^{2} + 4 x

What is the foci y= 2/(3.3)x^2-4x+6.6 ?
The foci y= 2/(3.3)x^2-4x+6.6 is (3.3,0.4125)