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Popular >

foci 3x^2+2y^2=6

Solution

foci

3 x^{2} + 2 y^{2} = 6

Solution

(0, 1), (0, - 1)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

3 x^{2} + 2 y^{2} = 6 :

Ellipse with center

(h, k) = (0, 0), b = 3, a = 2

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 3^{2} - 2^{2} : 1

(0, 0 + 1), (0, 0 - 1)

Refine

(0, 1), (0, - 1)

Popular Examples

vertices (x^2}{25}+\frac{y^2)/4 =1 vertices

\frac{x ^{2}}{25} + \frac{y ^{2}}{4} = 1

4 x^{2} + y^{2} = 16

foci y^2=-8x foci

y^{2} = - 8 x

x = y^{2} - 5

vertices y=x^2+2x-3 vertices

y = x^{2} + 2 x - 3

Frequently Asked Questions (FAQ)

What is the foci 3x^2+2y^2=6 ?
The foci 3x^2+2y^2=6 is (0,1),(0,-1)