What is the foci (x-4)^2=-8(y+2) ?

The foci (x-4)^2=-8(y+2) is (4,-4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (x-4)^2=-8(y+2)

foci

(x - 4)^{2} = - 8 (y + 2)

(4, - 4)

Solution steps

Rewrite

(x - 4)^{2} = - 8 (y + 2)

in the standard form:

4 (- 2) (y - (- 2)) = (x - 4)^{2}

(h, k) = (4, - 2), p = - 2

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(4, - 2)

along the y-axis

(4, - 2 + p)

= (4, - 2 + (- 2))

Refine

(4, - 4)

- 3 x^{2} - x + 4

y = \frac{( - 6 ( r + 4 r ^{2} ) + 9 r ^{2} + 6 r ) ^{2}}{9 r ^{2}}

y^{2} + 2 y - 4 x + 9 = 0

(x - 5) (x + 2)

(x + 1)^{2} + 3