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Popular >

foci 5x^2+7

Solution

foci

5 x^{2} + 7

Solution

(0, \frac{141}{20})

Solution steps

Rewrite

y = 5 x^{2} + 7

in the standard form:

4 \cdot \frac{1}{20} (y - 7) = (x - 0)^{2}

(h, k) = (0, 7), p = \frac{1}{20}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 7)

along the y-axis

(0, 7 + p)

= (0, 7 + \frac{1}{20})

Refine

(0, \frac{141}{20})

Popular Examples

foci 5x^2+4 foci

5 x^{2} + 4

foci 3y^2=16x foci

3 y^{2} = 16 x

foci 9x^2+24x+72y+16=0 foci

9 x^{2} + 24 x + 72 y + 16 = 0

foci y=8(x+2)^2-1 foci

y = 8 (x + 2)^{2} - 1

foci x^2+2x+7 foci

x^{2} + 2 x + 7

Frequently Asked Questions (FAQ)

What is the foci 5x^2+7 ?
The foci 5x^2+7 is (0, 141/20)