What is the foci (x+2)^2=20(y-5) ?

The foci (x+2)^2=20(y-5) is (-2,10)

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foci (x+2)^2=20(y-5)

foci

(x + 2)^{2} = 20 (y - 5)

(- 2, 10)

Solution steps

Rewrite

(x + 2)^{2} = 20 (y - 5)

in the standard form:

4 \cdot 5 (y - 5) = (x - (- 2))^{2}

(h, k) = (- 2, 5), p = 5

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 2, 5)

along the y-axis

(- 2, 5 + p)

= (- 2, 5 + 5)

Refine

(- 2, 10)

y^{2} = - x

x^{2} + 2 x - y = 3

4 x^{2} + 48 y + 12 x = 159

y = 2 x^{2} + 5 x - 3

(x + 9)^{2} = - 40 (y - 7)