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Popular >

foci x^2=8y+2x-33

Solution

foci

x^{2} = 8 y + 2 x - 33

Solution

(1, 6)

Solution steps

Rewrite

x^{2} = 8 y + 2 x - 33

in the standard form

4 \cdot 2 (y - 4) = (x - 1)^{2}

(h, k) = (1, 4), p = 2

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(1, 4)

along the y-axis

(1, 4 + p)

= (1, 4 + 2)

Refine

(1, 6)

Popular Examples

foci (x-4)^2=20(y+5)foci

(x - 4)^{2} = 20 (y + 5)

foci y= 1/2 (1-2x-x^2)foci

y = \frac{1}{2} (1 - 2 x - x^{2})

foci y= 1/4 (x+3)^2-5 foci

y = \frac{1}{4} (x + 3)^{2} - 5

foci-2x^2+3x foci

- 2 x^{2} + 3 x

foci x^2-5x+4 foci

x^{2} - 5 x + 4

Frequently Asked Questions (FAQ)

What is the foci x^2=8y+2x-33 ?
The foci x^2=8y+2x-33 is (1,6)