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Popular >

foci 20t-t^2

Solution

foci

20 t - t^{2}

Solution

(10, \frac{399}{4})

Solution steps

Rewrite

y = 20 t - t^{2}

in the standard form

4 (- \frac{1}{4}) (y - 100) = (t - 10)^{2}

(h, k) = (10, 100), p = - \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(10, 100)

along the y-axis

(10, 100 + p)

= (10, 100 + (- \frac{1}{4}))

Refine

(10, \frac{399}{4})

Popular Examples

foci y^2-12y-4x=-28 foci

y^{2} - 12 y - 4 x = - 28

foci (x-1)^2=8(y-k)foci

(x - 1)^{2} = 8 (y - k)

foci (y-4)^2=8(x-3)foci

(y - 4)^{2} = 8 (x - 3)

foci y=16x^2-25 foci

y = 16 x^{2} - 25

foci+2x^2-3x-1 foci

+ 2 x^{2} - 3 x - 1

Frequently Asked Questions (FAQ)

What is the foci 20t-t^2 ?
The foci 20t-t^2 is (10, 399/4)