What is the foci y=(x+9)(x+8) ?

The foci y=(x+9)(x+8) is (-17/2 ,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci y=(x+9)(x+8)

foci

y = (x + 9) (x + 8)

(- \frac{17}{2}, 0)

Solution steps

Rewrite

y = (x + 9) (x + 8)

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{1}{4})) = (x - (- \frac{17}{2}))^{2}

(h, k) = (- \frac{17}{2}, - \frac{1}{4}), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- \frac{17}{2}, - \frac{1}{4})

along the y-axis

(- \frac{17}{2}, - \frac{1}{4} + p)

= (- \frac{17}{2}, - \frac{1}{4} + \frac{1}{4})

Refine

(- \frac{17}{2}, 0)

(x + 1)^{2} = 2 (y + 2)

(x + 2)^{2} = - 8 (y + 3)

3 x^{2} + 6 x - 2

2 x^{2} - 4 x - 5

5 x^{2} - 40 x + 4 y + 85 = 0