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Popular >

foci x^2+8x-16

Solution

foci

x^{2} + 8 x - 16

Solution

(- 4, - \frac{127}{4})

Solution steps

Rewrite

y = x^{2} + 8 x - 16

in the standard form

4 \cdot \frac{1}{4} (y - (- 32)) = (x - (- 4))^{2}

(h, k) = (- 4, - 32), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 4, - 32)

along the y-axis

(- 4, - 32 + p)

= (- 4, - 32 + \frac{1}{4})

Refine

(- 4, - \frac{127}{4})

Popular Examples

foci y=+3x^2+24x-51 foci

y = + 3 x^{2} + 24 x - 51

foci x=(2y-1)^2 foci

x = (2 y - 1)^{2}

foci y=x^2-10x-24 foci

y = x^{2} - 10 x - 24

foci y=92x^2 foci

y = 92 x^{2}

foci y^2=40x foci

y^{2} = 40 x

Frequently Asked Questions (FAQ)

What is the foci x^2+8x-16 ?
The foci x^2+8x-16 is (-4,-127/4)