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Popular >

foci y=x^2-5x3

Solution

foci

y = x^{2} - 5 x 3

Solution

(\frac{15}{2}, - 56)

Solution steps

Rewrite

y = x^{2} - 5 x \cdot 3

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{225}{4})) = (x - \frac{15}{2})^{2}

(h, k) = (\frac{15}{2}, - \frac{225}{4}), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(\frac{15}{2}, - \frac{225}{4})

along the y-axis

(\frac{15}{2}, - \frac{225}{4} + p)

= (\frac{15}{2}, - \frac{225}{4} + \frac{1}{4})

Refine

(\frac{15}{2}, - 56)

Popular Examples

foci x^2-3x+4 foci

x^{2} - 3 x + 4

foci x=((y-3)^2)/8+5 foci

x = \frac{( y - 3 ) ^{2}}{8} + 5

foci y=-2x^2 foci

y = - 2 x^{2}

foci y=+1/7 x^2 foci

y = + \frac{1}{7} x^{2}

foci y=2x^2+x-15 foci

y = 2 x^{2} + x - 15

Frequently Asked Questions (FAQ)

What is the foci y=x^2-5x3 ?
The foci y=x^2-5x3 is (15/2 ,-56)