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Popular >

foci x^2-2x+5

Solution

foci

x^{2} - 2 x + 5

Solution

(1, \frac{17}{4})

Solution steps

Rewrite

y = x^{2} - 2 x + 5

in the standard form

4 \cdot \frac{1}{4} (y - 4) = (x - 1)^{2}

(h, k) = (1, 4), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(1, 4)

along the y-axis

(1, 4 + p)

= (1, 4 + \frac{1}{4})

Refine

(1, \frac{17}{4})

Popular Examples

foci (y-2)^2=8(x-5)foci

(y - 2)^{2} = 8 (x - 5)

foci (x+1)^2=(y+4)foci

(x + 1)^{2} = (y + 4)

foci y=-x^2+4x+3 foci

y = - x^{2} + 4 x + 3

foci x^2-4x-5y+7=0 foci

x^{2} - 4 x - 5 y + 7 = 0

foci (x-2)^2=12(y-1)foci

(x - 2)^{2} = 12 (y - 1)

Frequently Asked Questions (FAQ)

What is the foci x^2-2x+5 ?
The foci x^2-2x+5 is (1, 17/4)