What is the foci y=(40x^3)/(3x) ?

The foci y=(40x^3)/(3x) is (0, 3/160)

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foci y=(40x^3)/(3x)

foci

y = \frac{40 x ^{3}}{3 x}

(0, \frac{3}{160})

Solution steps

Rewrite

y = \frac{40 x ^{3}}{3 x}

in the standard form

4 \cdot \frac{3}{160} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{3}{160}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + \frac{3}{160})

Refine

(0, \frac{3}{160})

x^{2} + 10 x - 2 y + 21 = 0

y = 6 x^{2} + 5 x + 7

x = - \frac{1}{4} (y + 2)^{2} - 2

10 - x^{2}

x^{2} + 64