What is the foci-2x^2-8x-12 ?

The foci-2x^2-8x-12 is (-2,-33/8)

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foci-2x^2-8x-12

foci

- 2 x^{2} - 8 x - 12

(- 2, - \frac{33}{8})

Solution steps

Rewrite

y = - 2 x^{2} - 8 x - 12

in the standard form

4 (- \frac{1}{8}) (y - (- 4)) = (x - (- 2))^{2}

(h, k) = (- 2, - 4), p = - \frac{1}{8}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 2, - 4)

along the y-axis

(- 2, - 4 + p)

= (- 2, - 4 + (- \frac{1}{8}))

Refine

(- 2, - \frac{33}{8})

\frac{4 x ^{3} - 7 x ^{2} - 11 x + 5}{4 x + 5}

y = 3 x^{2} - 5 x

2 x^{2} - 12 x + 14 - 14 y = 0

x = - 3 y^{2} + 5

x^{2} + 4 x + 4 y = - 4