What is the foci 6x^2-49 ?

The foci 6x^2-49 is (0,-1175/24)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 6x^2-49

foci

6 x^{2} - 49

(0, - \frac{1175}{24})

Solution steps

Rewrite

y = 6 x^{2} - 49

in the standard form:

4 \cdot \frac{1}{24} (y - (- 49)) = (x - 0)^{2}

(h, k) = (0, - 49), p = \frac{1}{24}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, - 49)

along the y-axis

(0, - 49 + p)

= (0, - 49 + \frac{1}{24})

Refine

(0, - \frac{1175}{24})

x = + (y - 4)^{2} - 1

(x - 3)^{2} = - 4 (y - 1)

- (x - 1)^{2}

- x^{2} + 6 x - 9

- x^{2} - 6 x + 15