What is the vertices x^2 ?

The vertices x^2 is Minimum (0,0)

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vertices x^2

vertices

x^{2}

Minimum (0, 0)

Solution steps

y = x^{2}

The parabola parameters are:

a = 1, b = 0, c = 0

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{0}{2 \cdot 1}

Simplify

x_{v} = 0

Plug in

x_{v} = 0

to find the

y_{v}

value

y_{v} = 0

Therefore the parabola vertex is

(0, 0)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 1

Minimum (0, 0)

y^{2} = - 12 x

9 x^{2} - y^{2} - 36 x - 6 y + 18 = 0

9 y^{2} - 16 x^{2} = 144

(x - 1)^{2} + y^{2} = 1

16 x^{2} + 25 y^{2} = 400