What is the foci 2x^2+9x-56 ?

The foci 2x^2+9x-56 is (-9/4 ,-66)

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foci 2x^2+9x-56

foci

2 x^{2} + 9 x - 56

(- \frac{9}{4}, - 66)

Solution steps

Rewrite

y = 2 x^{2} + 9 x - 56

in the standard form

4 \cdot \frac{1}{8} (y - (- \frac{529}{8})) = (x - (- \frac{9}{4}))^{2}

(h, k) = (- \frac{9}{4}, - \frac{529}{8}), p = \frac{1}{8}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- \frac{9}{4}, - \frac{529}{8})

along the y-axis

(- \frac{9}{4}, - \frac{529}{8} + p)

= (- \frac{9}{4}, - \frac{529}{8} + \frac{1}{8})

Refine

(- \frac{9}{4}, - 66)

z^{2}

(x - 5)^{2} = 12 (y - 3)

x^{2} - 6 x - 5 y - 1 = 0

y = (x + 4)^{2}

(x + 1)^{2} = 12 (y - 3)