en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci x^2-16

Solution

foci

x^{2} - 16

Solution

(0, - \frac{63}{4})

Solution steps

Rewrite

y = x^{2} - 16

in the standard form:

4 \cdot \frac{1}{4} (y - (- 16)) = (x - 0)^{2}

(h, k) = (0, - 16), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, - 16)

along the y-axis

(0, - 16 + p)

= (0, - 16 + \frac{1}{4})

Refine

(0, - \frac{63}{4})

Popular Examples

foci (x+1)^2-2 foci

(x + 1)^{2} - 2

foci y=-4x^2 foci

y = - 4 x^{2}

foci y=(x^2-4)/2 foci

y = \frac{x ^{2} - 4}{2}

foci x=(y+1)^2-4 foci

x = (y + 1)^{2} - 4

foci (y-2)^2=12(x-3)foci

(y - 2)^{2} = 12 (x - 3)

Frequently Asked Questions (FAQ)

What is the foci x^2-16 ?
The foci x^2-16 is (0,-63/4)