What is the foci x^2+14x+26 ?

The foci x^2+14x+26 is (-7,-91/4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci x^2+14x+26

foci

x^{2} + 14 x + 26

(- 7, - \frac{91}{4})

Solution steps

Rewrite

y = x^{2} + 14 x + 26

in the standard form

4 \cdot \frac{1}{4} (y - (- 23)) = (x - (- 7))^{2}

(h, k) = (- 7, - 23), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 7, - 23)

along the y-axis

(- 7, - 23 + p)

= (- 7, - 23 + \frac{1}{4})

Refine

(- 7, - \frac{91}{4})

5 x^{2} - 11 x - 12

- (x - 3)^{2} - 4

y = + (x - 7)^{2} + 8

(y - 5)^{2} = - 8 x

(2 x - 3)^{2}