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Popular >

foci-x^2+10x-5

Solution

foci

- x^{2} + 10 x - 5

Solution

(5, \frac{79}{4})

Solution steps

Rewrite

y = - x^{2} + 10 x - 5

in the standard form

4 (- \frac{1}{4}) (y - 20) = (x - 5)^{2}

(h, k) = (5, 20), p = - \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(5, 20)

along the y-axis

(5, 20 + p)

= (5, 20 + (- \frac{1}{4}))

Refine

(5, \frac{79}{4})

Popular Examples

foci 16t^2+48t+4 foci

16 t^{2} + 48 t + 4

foci-0.4x^2-5 foci

- 0.4 x^{2} - 5

foci x^2+6x=4y-5 foci

x^{2} + 6 x = 4 y - 5

foci 18x^2+y=0 foci

18 x^{2} + y = 0

foci (x+1)^2=-3(y-6)foci

(x + 1)^{2} = - 3 (y - 6)

Frequently Asked Questions (FAQ)

What is the foci-x^2+10x-5 ?
The foci-x^2+10x-5 is (5, 79/4)