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Popular >

4<=-x^2-y

Solution

4 \leq - x^{2} - y

Solution

(h, k) = (0, - 4), p = - \frac{1}{4}

Solution steps

4 \leq - x^{2} - y

Rewrite

4 \leq - x^{2} - y

in the standard form:

4 (- \frac{1}{4}) (y - (- 4)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 4), p = - \frac{1}{4}

Popular Examples

18x^2-64x-14y+150=0

18 x^{2} - 64 x - 14 y + 150 = 0

x^2+y^2+6x-4y-12=0

x^{2} + y^{2} + 6 x - 4 y - 12 = 0

eccentricity 36x^2+y^2=36 eccentricity

36 x^{2} + y^{2} = 36

x^2-4x+y^2+6y-12=0

x^{2} - 4 x + y^{2} + 6 y - 12 = 0

(x^2}{16}+\frac{y^2)/4 =1

\frac{x ^{2}}{16} + \frac{y ^{2}}{4} = 1

Frequently Asked Questions (FAQ)

What is 4<=-x^2-y ?
The solution to 4<=-x^2-y is Parabola with (h,k)=(0,-4),p=-1/4