What is the foci 2x^2-12x-5 ?

The foci 2x^2-12x-5 is (3,-183/8)

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foci 2x^2-12x-5

foci

2 x^{2} - 12 x - 5

(3, - \frac{183}{8})

Solution steps

Rewrite

y = 2 x^{2} - 12 x - 5

in the standard form

4 \cdot \frac{1}{8} (y - (- 23)) = (x - 3)^{2}

(h, k) = (3, - 23), p = \frac{1}{8}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(3, - 23)

along the y-axis

(3, - 23 + p)

= (3, - 23 + \frac{1}{8})

Refine

(3, - \frac{183}{8})

(x - 5) (x - 3)

(y - 2) (y + 5)

x^{2} - 4 x + 24

(x - 5)^{2} = - 70 (y - 1)

6 x^{2} + 1