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Popular >

foci 40x-5x^2

Solution

foci

40 x - 5 x^{2}

Solution

(4, \frac{1599}{20})

Solution steps

Rewrite

y = 40 x - 5 x^{2}

in the standard form

4 (- \frac{1}{20}) (y - 80) = (x - 4)^{2}

(h, k) = (4, 80), p = - \frac{1}{20}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(4, 80)

along the y-axis

(4, 80 + p)

= (4, 80 + (- \frac{1}{20}))

Refine

(4, \frac{1599}{20})

Popular Examples

foci x=-3/8 (y-2)^2-1 foci

x = - \frac{3}{8} (y - 2)^{2} - 1

foci y=3x^2-7 foci

y = 3 x^{2} - 7

foci y=p(x-h)^2+k foci

y = p (x - h)^{2} + k

foci (x-3)^2=-12y foci

(x - 3)^{2} = - 12 y

foci y=3x^2+6 foci

y = 3 x^{2} + 6

Frequently Asked Questions (FAQ)

What is the foci 40x-5x^2 ?
The foci 40x-5x^2 is (4, 1599/20)