What is the foci 5x^2+6x-4 ?

The foci 5x^2+6x-4 is (-3/5 ,-23/4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 5x^2+6x-4

foci

5 x^{2} + 6 x - 4

(- \frac{3}{5}, - \frac{23}{4})

Solution steps

Rewrite

y = 5 x^{2} + 6 x - 4

in the standard form

4 \cdot \frac{1}{20} (y - (- \frac{29}{5})) = (x - (- \frac{3}{5}))^{2}

(h, k) = (- \frac{3}{5}, - \frac{29}{5}), p = \frac{1}{20}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- \frac{3}{5}, - \frac{29}{5})

along the y-axis

(- \frac{3}{5}, - \frac{29}{5} + p)

= (- \frac{3}{5}, - \frac{29}{5} + \frac{1}{20})

Refine

(- \frac{3}{5}, - \frac{23}{4})

y = 3 x^{2} - x - 4

y = x^{2} - 2 x - 9

y = x^{2} - 2 x - 5

x^{2} - 10 x - 20 y = - 185

x = - y^{2}