What is the foci (x-1)^2=-8(y2) ?

The foci (x-1)^2=-8(y2) is (1,-4)

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foci (x-1)^2=-8(y2)

foci

(x - 1)^{2} = - 8 (y 2)

(1, - 4)

Solution steps

Rewrite

(x - 1)^{2} = - 8 y \cdot 2

in the standard form:

4 (- 4) (y - 0) = (x - 1)^{2}

(h, k) = (1, 0), p = - 4

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(1, 0)

along the y-axis

(1, 0 + p)

= (1, 0 + (- 4))

Refine

(1, - 4)

(y - 3)^{2} = 12 (x + 2)

- 4 x^{2}

y = 2 x^{2} - 4 x

- 3 x^{2} + 3 x - 13

y = - 2 x^{2} + 5 x - 6