What is the foci (-4x-11)^2 ?

The foci (-4x-11)^2 is (-11/4 , 1/64)

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foci (-4x-11)^2

foci

(- 4 x - 11)^{2}

(- \frac{11}{4}, \frac{1}{64})

Solution steps

Rewrite

y = (- 4 x - 11)^{2}

in the standard form:

4 \cdot \frac{1}{64} (y - 0) = (x - (- \frac{11}{4}))^{2}

(h, k) = (- \frac{11}{4}, 0), p = \frac{1}{64}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- \frac{11}{4}, 0)

along the y-axis

(- \frac{11}{4}, 0 + p)

= (- \frac{11}{4}, 0 + \frac{1}{64})

Refine

(- \frac{11}{4}, \frac{1}{64})

2 x^{2} - 8 x + 3

(x - 3) (x + 1)

y = x^{2} + 5 x - 24

y = - x^{2} + 2 x - 5

y = 2 x^{2} - 1 + 5 x