What is the foci 4.905x^2+8x-30 ?

The foci 4.905x^2+8x-30 is (-0.81549…,-33.21100…)

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foci 4.905x^2+8x-30

foci

4.905 x^{2} + 8 x - 30

(- 0.81549 \dots, - 33.21100 \dots)

Solution steps

Rewrite

y = 4.905 x^{2} + 8 x - 30

in the standard form

4 \cdot 0.05096 \dots (y - (- 33.26197 \dots)) = (x - (- 0.81549 \dots))^{2}

(h, k) = (- 0.81549 \dots, - 33.26197 \dots), p = 0.05096 \dots

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 0.81549 \dots, - 33.26197 \dots)

along the y-axis

(- 0.81549 \dots, - 33.26197 \dots + p)

= (- 0.81549 \dots, - 33.26197 \dots + 0.05096 \dots)

Refine

(- 0.81549 \dots, - 33.21100 \dots)

x = - \frac{1}{2} (y - 2)^{2} + 5

(x + 6)^{2} = - 8 (y + 9)

(2 + x)^{2}

\frac{40 x ^{3}}{3 x}

y = 10 x - x^{2}

What is the foci 4.905x^2+8x-30 ?
The foci 4.905x^2+8x-30 is (-0.81549…,-33.21100…)