en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci y^2=16x-8

Solution

foci

y^{2} = 16 x - 8

Solution

(\frac{9}{2}, 0)

Solution steps

Rewrite

y^{2} = 16 x - 8

in the standard form:

4 \cdot 4 (x - \frac{1}{2}) = (y - 0)^{2}

(h, k) = (\frac{1}{2}, 0), p = 4

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(\frac{1}{2}, 0)

along the x-axis

(\frac{1}{2} + p, 0)

= (\frac{1}{2} + 4, 0)

Refine

(\frac{9}{2}, 0)

Popular Examples

foci (x-6)^2 foci

(x - 6)^{2}

foci (x^2)/2+1 foci

\frac{x ^{2}}{2} + 1

foci (y+3)^2=sqrt(48)(x-5)foci

(y + 3)^{2} = 48 (x - 5)

foci x^2-7x+12 foci

x^{2} - 7 x + 12

foci x^2-6y=0 foci

x^{2} - 6 y = 0

Frequently Asked Questions (FAQ)

What is the foci y^2=16x-8 ?
The foci y^2=16x-8 is (9/2 ,0)