What is the foci-16x+y^2+2y-63=0 ?

The foci-16x+y^2+2y-63=0 is (0,-1)

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foci-16x+y^2+2y-63=0

foci

- 16 x + y^{2} + 2 y - 63 = 0

(0, - 1)

Solution steps

Rewrite

- 16 x + y^{2} + 2 y - 63 = 0

in the standard form

4 \cdot 4 (x - (- 4)) = (y - (- 1))^{2}

(h, k) = (- 4, - 1), p = 4

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(- 4, - 1)

along the x-axis

(- 4 + p, - 1)

= (- 4 + 4, - 1)

Refine

(0, - 1)

y = - x^{2} - 6 x + 15

(x + 3) + (y - 2)^{2} = 0

x = 2 y - y^{2}

- \frac{( x + 3 ) ^{2}}{20} + 1

y = 3 x^{2} - 15 x + 6