What is the foci y=6x^2-1 ?

The foci y=6x^2-1 is (0,-23/24)

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foci y=6x^2-1

foci

y = 6 x^{2} - 1

(0, - \frac{23}{24})

Solution steps

Rewrite

y = 6 x^{2} - 1

in the standard form:

4 \cdot \frac{1}{24} (y - (- 1)) = (x - 0)^{2}

(h, k) = (0, - 1), p = \frac{1}{24}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, - 1)

along the y-axis

(0, - 1 + p)

= (0, - 1 + \frac{1}{24})

Refine

(0, - \frac{23}{24})

1.5 + 17.67 t - 4.905 t^{2}

y = (3 x - 4) (4 x - 3) - 2 x

x^{2} - 4 x - y + 3 = 0

- 2 x^{2} + 24 x + y - 70 = 0

y = - 4 x^{2} + 1