What is the foci-0.3x^2+2x+3 ?

The foci-0.3x^2+2x+3 is (3.33333…,5.5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci-0.3x^2+2x+3

foci

- 0.3 x^{2} + 2 x + 3

(3.33333 \dots, 5.5)

Solution steps

Rewrite

y = - 0.3 x^{2} + 2 x + 3

in the standard form

4 (- 0.83333 \dots) (y - 6.33333 \dots) = (x - 3.33333 \dots)^{2}

(h, k) = (3.33333 \dots, 6.33333 \dots), p = - 0.83333 \dots

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(3.33333 \dots, 6.33333 \dots)

along the y-axis

(3.33333 \dots, 6.33333 \dots + p)

= (3.33333 \dots, 6.33333 \dots + (- 0.83333 \dots))

Refine

(3.33333 \dots, 5.5)

6 x^{2} - 3 x 5

(x + 2)^{2} = - 8 y

x^{2} - 5 x + 3

5 x - x^{2}

y = x^{2} + 2 x - 3