What is the foci y^2=(25)/(-2)x ?

The foci y^2=(25)/(-2)x is (-25/8 ,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci y^2=(25)/(-2)x

foci

y^{2} = \frac{25}{- 2} x

(- \frac{25}{8}, 0)

Solution steps

Rewrite

y^{2} = \frac{25}{- 2} x

in the standard form:

4 (- \frac{25}{8}) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - \frac{25}{8}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + (- \frac{25}{8}), 0)

Refine

(- \frac{25}{8}, 0)

- x^{2} - 3

x^{2} - 4 x - 12 y - 20 = 0

- 2 x^{2} + 6 x

y = x^{2} + 2 x + 1

x = 3 (y - 2)^{2} - 7