What is the foci (x-4)^2=-12(y-3) ?

The foci (x-4)^2=-12(y-3) is (4,0)

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foci (x-4)^2=-12(y-3)

foci

(x - 4)^{2} = - 12 (y - 3)

(4, 0)

Solution steps

Rewrite

(x - 4)^{2} = - 12 (y - 3)

in the standard form:

4 (- 3) (y - 3) = (x - 4)^{2}

(h, k) = (4, 3), p = - 3

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(4, 3)

along the y-axis

(4, 3 + p)

= (4, 3 + (- 3))

Refine

(4, 0)

x^{2} - 2 x - 24

X^{2} - 5 X - 24

(x - 3)^{2} = 12 (y - 2)

(x - 102.05) \frac{498.625 - x}{0.1249}

x^{2} + 9 x + 18