What is the directrix y= 1/12 x^2 ?

The directrix y= 1/12 x^2 is y=-3

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directrix y= 1/12 x^2

directrix

y = \frac{1}{12} x^{2}

y = - 3

Solution steps

Rewrite

y = \frac{1}{12} x^{2}

in the standard form:

4 \cdot 3 (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = 3

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - 3

Refine

y = - 3

x^{2} + y^{2} - 6 x + 5 = 0

y^{2} = x + 2

x^{2} + 2 y^{2} = 2

f (x) = x^{2} - 4 x

2 y^{2} + x + 20 y + 51 = 0