What is the directrix 9y^2-6y-9-x=0 ?

The directrix 9y^2-6y-9-x=0 is x=-361/36

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directrix 9y^2-6y-9-x=0

directrix

9 y^{2} - 6 y - 9 - x = 0

x = - \frac{361}{36}

Solution steps

Rewrite

9 y^{2} - 6 y - 9 - x = 0

in the standard form

4 \cdot \frac{1}{36} (x - (- 10)) = (y - \frac{1}{3})^{2}

(h, k) = (- 10, \frac{1}{3}), p = \frac{1}{36}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(- 10, \frac{1}{3})

x-coordinate

x = - 10 - p

x = - 10 - \frac{1}{36}

Refine

x = - \frac{361}{36}

2 X^{2}

x^{2} + 3 x - 4

y = x^{2} - 4 x + 4

5 x (2 x + 4) - 3 x

x^{2} + 12 y = 0