What is the directrix 2x^2-2 ?

The directrix 2x^2-2 is y=-17/8

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directrix 2x^2-2

directrix

2 x^{2} - 2

y = - \frac{17}{8}

Solution steps

Rewrite

y = 2 x^{2} - 2

in the standard form:

4 \cdot \frac{1}{8} (y - (- 2)) = (x - 0)^{2}

(h, k) = (0, - 2), p = \frac{1}{8}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, - 2)

y-coordinate

y = - 2 - p

y = - 2 - \frac{1}{8}

Refine

y = - \frac{17}{8}

2 x^{2} + 3

x^{2} + x + 1

4 + 2 x - x^{2}

\frac{1}{4} x^{2} + x - 8

x^{2} - 8 x - 240