What is the directrix-2x^2-4x+34 ?

The directrix-2x^2-4x+34 is y= 289/8

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directrix-2x^2-4x+34

directrix

- 2 x^{2} - 4 x + 34

y = \frac{289}{8}

Solution steps

Rewrite

y = - 2 x^{2} - 4 x + 34

in the standard form

4 (- \frac{1}{8}) (y - 36) = (x - (- 1))^{2}

(h, k) = (- 1, 36), p = - \frac{1}{8}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- 1, 36)

y-coordinate

y = 36 - p

y = 36 - (- \frac{1}{8})

Refine

y = \frac{289}{8}

2 x^{2} - 5 x + 5

y = \frac{x ^{2} 5 x 8}{x 3}

(x + 5)^{2} = - 20 (y - 2)

x^{2} + 4 x - 3

x^{2} - y = 0