What is the directrix 3x^2-x-4 ?

The directrix 3x^2-x-4 is y=-25/6

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directrix 3x^2-x-4

directrix

3 x^{2} - x - 4

y = - \frac{25}{6}

Solution steps

Rewrite

y = 3 x^{2} - x - 4

in the standard form

4 \cdot \frac{1}{12} (y - (- \frac{49}{12})) = (x - \frac{1}{6})^{2}

(h, k) = (\frac{1}{6}, - \frac{49}{12}), p = \frac{1}{12}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(\frac{1}{6}, - \frac{49}{12})

y-coordinate

y = - \frac{49}{12} - p

y = - \frac{49}{12} - \frac{1}{12}

Refine

y = - \frac{25}{6}

y = x^{2} - 10 x - 4

y = - 3 x^{2}

y = 3.1 + 6.6 x - 2.3 x^{2}

y = 3 x^{2} 4

- 7 x^{2}