What is x^2+2x+y^2=8 ?

The solution to x^2+2x+y^2=8 is Circle with (a,b)=(-1,0),r=3

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x^2+2x+y^2=8

x^{2} + 2 x + y^{2} = 8

(a, b) = (- 1, 0), r = 3

Solution steps

x^{2} + 2 x + y^{2} = 8

Rewrite

x^{2} + 2 x + y^{2} = 8

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 0)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 1, 0), r = 3

\frac{y ^{2}}{16} - \frac{x ^{2}}{9} = 1

4 x^{2} - 9 y^{2} = 36

9 y^{2} - 4 x^{2} = 36

\frac{x ^{2}}{144} - \frac{y ^{2}}{25} = 1

f (x) = 2 x^{2}

What is x^2+2x+y^2=8 ?
The solution to x^2+2x+y^2=8 is Circle with (a,b)=(-1,0),r=3