What is the directrix y=-7(x-8)^2+6 ?

The directrix y=-7(x-8)^2+6 is y= 169/28

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

directrix y=-7(x-8)^2+6

directrix

y = - 7 (x - 8)^{2} + 6

y = \frac{169}{28}

Solution steps

Rewrite

y = - 7 (x - 8)^{2} + 6

in the standard form:

4 (- \frac{1}{28}) (y - 6) = (x - 8)^{2}

(h, k) = (8, 6), p = - \frac{1}{28}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(8, 6)

y-coordinate

y = 6 - p

y = 6 - (- \frac{1}{28})

Refine

y = \frac{169}{28}

y = x^{2} - 9 x + 20

x^{2} - 6 x + 5 y = 34

y = (x - 4)^{2} - 9

y = \frac{1}{3} x^{2} + 6 x + 10

F = \frac{m v ^{2}}{r}