What is the directrix x=-8y^2 ?

The directrix x=-8y^2 is x= 1/32

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directrix x=-8y^2

directrix

x = - 8 y^{2}

x = \frac{1}{32}

Solution steps

Rewrite

x = - 8 y^{2}

in the standard form:

4 (- \frac{1}{32}) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - \frac{1}{32}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- \frac{1}{32})

Refine

x = \frac{1}{32}

y = 4 x^{2} + 23 x - 6

4 - X^{2}

x^{2} + 4 x - 4 y = 0

\frac{1}{2} (x^{2} - 4 x + 2)

- x^{2} + 8 x - 7