What is the directrix y^2=10x ?

The directrix y^2=10x is x=-5/2

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directrix y^2=10x

directrix

y^{2} = 10 x

x = - \frac{5}{2}

Solution steps

Rewrite

y^{2} = 10 x

in the standard form:

4 \cdot \frac{5}{2} (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = \frac{5}{2}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - \frac{5}{2}

Refine

x = - \frac{5}{2}

x^{2} + 1

y = - (x + 3)^{2} - 1

y = 9 x^{2}

x = \frac{1}{8} y^{2}

y = 2 x^{2} + 6 x + 10