What is the directrix (x-2)^2=-(y-1) ?

The directrix (x-2)^2=-(y-1) is y= 5/4

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directrix (x-2)^2=-(y-1)

directrix

(x - 2)^{2} = - (y - 1)

y = \frac{5}{4}

Solution steps

Rewrite

(x - 2)^{2} = - (y - 1)

in the standard form:

4 (- \frac{1}{4}) (y - 1) = (x - 2)^{2}

(h, k) = (2, 1), p = - \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(2, 1)

y-coordinate

y = 1 - p

y = 1 - (- \frac{1}{4})

Refine

y = \frac{5}{4}

y = x^{2} - 2 x + 5

y = - 3 x^{2} + 6 x - 1

X^{2} - 5 X - 24

y = 2 x^{2} + 5 x + 2

y^{2} + 4 y + 8 x - 12 = 0