What is the directrix x^2+6y=0 ?

The directrix x^2+6y=0 is y= 3/2

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directrix x^2+6y=0

directrix

x^{2} + 6 y = 0

y = \frac{3}{2}

Solution steps

Rewrite

x^{2} + 6 y = 0

in the standard form:

4 (- \frac{3}{2}) (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = - \frac{3}{2}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - (- \frac{3}{2})

Refine

y = \frac{3}{2}

y = 2 x^{2} - 19 x + 9

- 2 x^{2}

\frac{x ^{5} + x ^{4} + x ^{3} + x ^{2} + x + 1}{x ^{3} + 1}

y = x^{2} - 15 x

- x^{2} + 8 x - 10