What is the directrix 8y=x^2 ?

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directrix 8y=x^2

directrix

8 y = x^{2}

y = - 2

Solution steps

Rewrite

8 y = x^{2}

in the standard form:

4 \cdot 2 (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = 2

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - 2

Refine

y = - 2

x^{2} = 24 (y - 8)

x^{2} = 36 y

(x + 4)^{2} - 1

\frac{x ^{3} + 6 x ^{2} + 9 x}{x + 3}

y^{2} + 4 x - 8 y + 12 = 0