What is the directrix y= 1/4 x^2 ?

The directrix y= 1/4 x^2 is y=-1

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directrix y= 1/4 x^2

directrix

y = \frac{1}{4} x^{2}

y = - 1

Solution steps

Rewrite

y = \frac{1}{4} x^{2}

in the standard form:

4 \cdot 1 \cdot (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = 1

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - 1

Refine

y = - 1

y = 2 x^{2} - 2

y = 4 x^{2} + 8 x - 20

2 x^{2} - 4 x + 15

y = - \frac{1}{8} x^{2}

y = 7 - 2 x - 3 x^{2}