What is the directrix x^2=-20y ?

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directrix x^2=-20y

directrix

x^{2} = - 20 y

y = 5

Solution steps

Rewrite

x^{2} = - 20 y

in the standard form:

4 (- 5) (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = - 5

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - (- 5)

Refine

y = 5

y = 3 x^{2} - 2 x - 6

t^{2} + 2 t - 48

x^{2} + 9

2 x^{2} - 1 - (5 x - 6)

y^{2} - 4 x - 4 = 0