What is the directrix y=-x^2+5 ?

The directrix y=-x^2+5 is y= 21/4

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directrix y=-x^2+5

directrix

y = - x^{2} + 5

y = \frac{21}{4}

Solution steps

Rewrite

y = - x^{2} + 5

in the standard form:

4 (- \frac{1}{4}) (y - 5) = (x - 0)^{2}

(h, k) = (0, 5), p = - \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 5)

y-coordinate

y = 5 - p

y = 5 - (- \frac{1}{4})

Refine

y = \frac{21}{4}

y = - x^{2} + 10 x

y = x^{2} + 3

y = x^{2} + 1

y = x^{2} + x - 1

4 x^{2} - 8 x - 3 y - 2 = 0