What is the directrix-2x^2+12x-2 ?

The directrix-2x^2+12x-2 is y= 129/8

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directrix-2x^2+12x-2

directrix

- 2 x^{2} + 12 x - 2

y = \frac{129}{8}

Solution steps

Rewrite

y = - 2 x^{2} + 12 x - 2

in the standard form

4 (- \frac{1}{8}) (y - 16) = (x - 3)^{2}

(h, k) = (3, 16), p = - \frac{1}{8}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(3, 16)

y-coordinate

y = 16 - p

y = 16 - (- \frac{1}{8})

Refine

y = \frac{129}{8}

4 x^{2} - 8 x - 3

y = - 9 x^{2}

y - 2 = 3 (x - 5)^{2}

y = (x - 12)^{2}

x \leq y^{2}