What is the directrix y^2=x-3 ?

The directrix y^2=x-3 is x= 11/4

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directrix y^2=x-3

directrix

y^{2} = x - 3

x = \frac{11}{4}

Solution steps

Rewrite

y^{2} = x - 3

in the standard form:

4 \cdot \frac{1}{4} (x - 3) = (y - 0)^{2}

(h, k) = (3, 0), p = \frac{1}{4}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(3, 0)

x-coordinate

x = 3 - p

x = 3 - \frac{1}{4}

Refine

x = \frac{11}{4}

y = x^{2} - 4 x - 4

+ y^{2} - y - x + 1 = 0

y = - x^{2} - 6 x - 7

2 x^{2} - 13 x - 7

\frac{x ^{2} x ^{1}}{x}